K2CO3+2HCl→2KCl+CO2+H2Ocap K sub 2 cap C cap O sub 3 plus 2 cap H cap C l right arrow 2 cap K cap C l plus cap C cap O sub 2 plus cap H sub 2 cap O , 0.0100 mol of CO2cap C cap O sub 2 corresponds to 1.38 g of K2CO3cap K sub 2 cap C cap O sub 3 , resulting in .
Modern students would use a P-table and an ICE chart. 1972 students had to: 1972 ap chemistry free response answers